Alkenes react with water in the presence of acid as a catalyst to form alcohols: $CH_3-CH=CH_2 + H_2O \xrightarrow{H^{+}} CH_3-CH(OH)-CH_3$. The reaction takes place in accordance with:

Consider compounds $A$,$B$ and $C$ with following structural formulae: $A = CH_{3} - CH_{2} - CH_{2} - CH_{2} - CH_{2} - OH$,$B = CH_{2} = CH - CH_{2} - CH_{2} - CH_{3}$,$C = HO - CH_{2} - CH_{2} - CH(OH) - CH_{3}$. For the conversion of $B$ from $A$,reagent $(D)$ required is . . . . . . and structural formula of product $(E)$ obtained when $C$ undergoes same reaction using excess reagent $(D)$ is . . . . . . .

Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of:

The product $(A)$ of the given alkoxymercuration-demercuration reaction is:

Baeyer's reagent is used in the laboratory for

An alkene $X$ with formula $C_4H_8$ does not exhibit geometrical isomerism. In the conversion of $X$ to $Y$,the correct sequence of reagents $A$ and $B$ used are ($Y$ gives iodoform test):
$X$ $\xrightarrow{A} \text{Intermediate}$ $\xrightarrow{B} Y$